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508 lines
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Markdown
508 lines
15 KiB
Markdown
---
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layout: post
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title: "Static Polymorphism"
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description: "Emulating Traits in C++"
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category:
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tags: [python]
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---
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Other languages have done similar things (interfaces in Java), but think the Rust comparison is
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useful because both languages are "system."
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# System Differences
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Worth noting differences in goals: polymorphism in C++ is only duck typing. Means that static
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polymorphism happens separate from visibility, overloading, etc.
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Rust's trait system is different (need a better way to explain that) which allows for trait markers,
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auto-deriving, arbitrary self.
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# Simple Example
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Accept parameter types, return known type. Also needs to be generic over parameter types.
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# Generic return
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Same name and parameter signature, but return different types - `AsRef`
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# Associated types
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`.as_iter()`, and the iterator `Item` type
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# decltype and compiler-named types
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Rust has some types named by the compiler, but inaccessible in traits; can't return `impl SomeTrait`
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from traits. Can return `impl Future` from free functions and structs, but traits can't use
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compiler-generated types (associated types still need to name the type).
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Can have traits return references (`&dyn Trait`), but uses vtable (so no longer statically
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polymorphic), and very likely get into all sorts of lifetime issues. Can use `Box<dyn Trait>` trait
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objects to avoid lifetime issues, but again, uses vtable.
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C++ doesn't appear to have the same restrictions, mostly because the "contract" is just duck typing.
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# Require static methods on a class?
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Shouldn't be too hard - `T::some_method()` should be compilable.
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# Default implementation
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First: example of same name, different arguments. Not possible in Rust.
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```rust
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trait MyTrait {
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// This is illegal in Rust, even though name-mangling is unique:
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// fn method(&self, value: usize) -> usize;
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// Works if you rename the method, but is a pain to type:
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fn method_with_options(&self, value: usize) -> usize;
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fn method(&self) -> usize {
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self.method_with_options(42);
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}
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}
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struct MyStruct {}
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impl MyTrait for MyStruct {
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fn method_with_options(&self, value: usize) -> usize {
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println!("{}", value);
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value
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}
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}
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```
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Second: example of same name, different arguments, but can't provide default implementation.
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```c++
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template <typename T>
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concept MyTrait = requires (T a) {
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{ a.method(declval<std::size_t>()) } -> std::same_as<std::size_t>,
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{ a.method() } -> std::same_as<std::size_t>,
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}
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// Each class must implement both `method` signatures.
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class MyClass {
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public:
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std::size_t method(std::size_t value) {
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std::cout << value << std::endl;
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return value;
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}
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std::size_t method() {
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return method(42);
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}
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};
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// Can write free functions as the default and then call explicitly, but for trivial
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// implementations (replacing defaults) it's not likely to be worth it.
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auto method_default_(auto MyTrait this) std::size_t {
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return this.method(42);
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}
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class MyClassDefault {
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public:
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std::size_t method(std::size_t value) {
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std::cout << value << std::endl;
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return value;
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}
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std::size_t method() {
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return method_default_(this);
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}
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}
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```
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# Method Qualifiers
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Rust allows declaring immutable, mutable, and consumed arguments (including `self`).
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C++ can use `const_cast` to assert "constness" of `this` and method arguments:
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```c++
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#include <concepts>
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#include <cstdint>
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template <typename T>
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concept ConstMethod = requires (T a) {
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{ const_cast<const T&>(a).method() } -> std::same_as<std::uint64_t>;
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{ a.another(std::declval<const std::uint64_t>()) } -> std::same_as<std::uint64_t>;
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};
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std::uint64_t my_function(ConstMethod auto a) {
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return a.method();
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}
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class HasConst {
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public:
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std::uint64_t method() const {
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return 42;
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}
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// NOTE: non-`const` value is also acceptable here.
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std::uint64_t another(const std::uint64_t value) {
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return value;
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}
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};
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class WithoutConst {
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public:
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std::uint64_t method() {
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return 42;
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}
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std::uint64_t another(const std::uint64_t value) {
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return value;
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}
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};
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int main() {
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auto x = HasConst{};
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my_function(x);
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auto y = WithoutConst{};
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my_function(y);
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}
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```
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```text
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<source>:32:18: error: use of function 'uint64_t my_function(auto:1) [with auto:1 = WithoutConst; uint64_t = long unsigned int]' with unsatisfied constraints
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32 | my_function(y);
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| ^
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<source>:9:15: note: declared here
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9 | std::uint64_t my_function(ConstMethod auto a) {
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| ^~~~~~~~~~~
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<source>:9:15: note: constraints not satisfied
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<source>: In instantiation of 'uint64_t my_function(auto:1) [with auto:1 = WithoutConst; uint64_t = long unsigned int]':
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<source>:32:18: required from here
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<source>:5:9: required for the satisfaction of 'ConstMethod<auto:1>' [with auto:1 = WithoutConst]
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<source>:5:23: in requirements with 'T a' [with T = WithoutConst]
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<source>:6:37: note: the required expression 'const_cast<const T&>(a).method()' is invalid, because
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6 | { const_cast<const T&>(a).method() } -> std::same_as<std::uint64_t>;
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| ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~
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<source>:6:37: error: passing 'const WithoutConst' as 'this' argument discards qualifiers [-fpermissive]
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<source>:22:19: note: in call to 'uint64_t WithoutConst::method()'
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22 | std::uint64_t method() {
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| ^~~~~~
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```
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...but difficult to do anything beyond that. Is there a way to declare methods must be `noexcept`,
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`volatile`, etc.? Also can't have methods that consume `this`.
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# Implement methods on remote types
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Rust allows both arbitrary `self` and extension traits. Arbitrary self forms the basis of the
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`async` system in Rust. Extension traits form basis of `futures` library. Accomplish effectively the
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same thing, but for concrete types and traits respectively.
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UFCS would achieve the same effect, but unclear if/when it will be available:
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https://dancrn.com/2020/08/02/ufcs-in-clang.html
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Can use free functions in the meantime, but having the IDE auto-complete `.<the next thing>` is
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exceedingly useful, as opposed to looking through all functions in a namespace.
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Can also sub-class or implicitly convert to a wrapper:
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```c++
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#include <concepts>
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#include <cstdint>
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class SomeRemoteClass {};
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template<typename T>
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concept MyConcept = requires (T a) {
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{ a.do_something() } -> std::same_as<std::uint64_t>;
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};
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// Note: It's unsafe to move `SomeRemoteClass`, so we accept by reference
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// Requiring SomeRemoteClass be copy-constructible would also be OK.
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class LocalImpl {
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public:
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LocalImpl(const SomeRemoteClass &remote): remote_{remote} {};
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std::uint64_t do_something() {
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return 42;
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}
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private:
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const SomeRemoteClass &remote_;
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};
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auto auto_func(MyConcept auto value) {
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auto x = value.do_something();
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}
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void regular_func(LocalImpl value) {
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auto x = value.do_something();
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}
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int main() {
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SomeRemoteClass x {};
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// This _will not_ compile because `auto` doesn't trigger the conversion to `LocalImpl`
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//auto_func(x);
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// This _will_ compile because the function signature declares a concrete class for which an
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// implicit conversion is available. It just so happens that `LocalImpl` satisfies `MyConcept`.
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regular_func(x);
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}
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```
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The `LocalImpl` wrapper could be extended to handle additional remote types using template
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specialization or holding an internal `std::variant`, but that misses the point: we want to write
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code that accepts anything that satisfies `MyConcept`. When we write functions that require a
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specific wrapper, we're being overly restrictive, and obfuscating our intentions (we don't actually
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care about the wrapper, it's just there for ease-of-use).
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Can use some overloading/specialization tricks for ease of use:
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```c++
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auto some_func_(MyConcept auto value) -> void {
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auto x = value.do_something();
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}
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auto some_func(MyConcept auto value) -> void {
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some_func_(value);
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}
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void some_func(LocalImpl value) {
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some_func_(value);
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}
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```
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Need to be careful though:
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```c++
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auto some_func(MyConcept auto value) -> void {
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auto x = value.do_something();
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}
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void some_func(LocalImpl value) {
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// NOTE: Because `LocalImpl` is more specific than `auto`, this is a recursive call and
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// will overflow the stack.
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// We use `some_func_` above to uniquely name the function we actually want to call.
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some_func(value);
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}
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```
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Potentially worth mentioning orphan rule in Rust as limit to extension methods - can't implement
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remote traits for remote types.
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# Checking a type fulfills the concept
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With concepts, you find out that there's an issue only when you attempt to use it. Traits in Rust
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will let you know during implementation that something is wrong (there's a local error).
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https://www.ecorax.net/as-above-so-below-1/
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Can use `static_assert` to kinda make sure a contract is fulfilled:
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```c++
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#include <cstdint>
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#include <type_traits>
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template<typename T>
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constexpr bool has_method = std::is_same_v<decltype(std::declval<T>().method()), std::uint64_t>;
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class WithMethod {
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public:
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std::uint64_t method() { return 0; }
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};
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static_assert(has_method<WithMethod>);
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class WithoutMethod {};
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// <source>: In instantiation of 'constexpr const bool has_method<WithoutMethod>':
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// <source>:16:16: required from here
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// <source>:5:71: error: 'class WithoutMethod' has no member named 'method'
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// 5 | constexpr bool has_method = std::is_same_v<decltype(std::declval<T>().method()), std::uint64_t>;
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// | ~~~~~~~~~~~~~~~~~~^~~~~~
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// <source>:16:15: error: non-constant condition for static assertion
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// 16 | static_assert(has_method<WithoutMethod>);
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// |
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static_assert(has_method<WithoutMethod>);
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```
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We'd rather the example fail the static assert, rather than have an error on the `decltype`, but it
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does get the job done; we're told explicitly that `WithoutMethod` has no member `method`, so the
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error message for `decltype()` is actually much nicer than the `static_assert`.. Can use
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[custom SFINAE](https://stackoverflow.com/a/257382) or
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[experimental](https://stackoverflow.com/a/22014784)
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[type traits](http://en.cppreference.com/w/cpp/experimental/is_detected) to fix those issues, but
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mostly please just use concepts.
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# Potentially excluded
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Some ideas related to traits, but that I'm not sure sufficiently fit the theme. May be worth
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investigating in a future post?
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## Visibility
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Worth acknowledging that C++ can do interesting things with `protected`, `friend`, and others, that
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Rust can't. However, Rust can limit trait implementations to current crate ("sealed traits"), where
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C++ concepts are purely duck typing.
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## Move/consume `self` as opposed to `&self`?
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Not exactly polymorphism, but is a significant feature of Rust trait system. Is there a way to force
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`std::move(object).method()`? C++ can still use objects after movement makes them invalid, so not
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sure that it makes conceptual sense - it's your job to prevent use-after-move, not the compiler's.
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## Automatic markers?
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Alternately, conditional inheritance based on templates?
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## Arbitrary `self`
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Handled as part of section on `impl Trait` for remote type, not sure this needs it's own section.
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Forms the basis for Rust's async system, but used very rarely aside from that.
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[`std::enable_shared_from_this`](https://en.cppreference.com/w/cpp/memory/enable_shared_from_this)
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`enable_unique_from_this` doesn't make a whole lot of sense, but Rust can do it:
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```rust
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struct MyStruct {}
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impl MyStruct {
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fn my_function(self: &Box<Self>) {}
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}
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fn main() {
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let unboxed = MyStruct {};
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// error[E0599]: no method named `my_function` found for struct `MyStruct` in the current scope
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// unboxed.my_function();
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let boxed = Box::new(MyStruct {});
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boxed.my_function();
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boxed.my_function();
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}
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```
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Interestingly enough, can't bind `static` version using equality:
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```c++
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#include <iterator>
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#include <vector>
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#include <concepts>
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std::uint64_t free_get_value() {
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return 24;
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}
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class MyClass {
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public:
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// <source>:11:47: error: invalid pure specifier (only '= 0' is allowed) before ';' token
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std::uint64_t get_value() = free_get_value;
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};
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int main() {
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auto x = MyClass {};
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}
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```
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---
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Turns out the purpose of `enable_shared_from_this` is so that you can create new shared instances of
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yourself from within yourself, it doesn't have anything to do with enabling extra functionality
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depending on whether you're owned by a shared pointer. _At best_, you could have other runtime
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checks to see if you're owned exclusively, or as part of some other smart pointer, but the type
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system can't enforce that. And if you're _not_ owned by that smart pointer, what then? Exceptions?
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UFCS would be able to help with this - define new methods like:
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```c++
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template<>
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void do_a_thing(std::unique_ptr<MyType> value) {}
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```
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In this case, the extension is actually on `unique_ptr`, but the overload resolution applies only to
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pointers of `MyType`. Note that `shared_ptr` and others seem to work by overloading `operator ->` to
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proxy function calls to the delegates; you could inherit `std::shared_ptr` and specialize the
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template to add methods for specific classes I guess? But it's still inheriting `shared_ptr`, you
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can't define things directly on it.
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Generally, "you can just use free functions" seems like a shoddy explanation. We could standardize
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overload `MyClass_init` as a constructor and function similar to C, etc., but the language is
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designed to assist us so we don't have to do crap like that. I do hope UFCS becomes a thing.
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That said, it is interesting that for Rust, arbitrary self can be replaced with traits:
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```rust
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trait MyTrait {
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fn my_function(&self);
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}
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impl MyTrait for Box<MyStruct> {
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fn my_function(&self) {}
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}
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```
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Just have to make sure that `MyTrait` is in scope all the time, and that's not fun. Ultimately, Rust
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kinda already has UFCS. It's only "kinda" because you have to bring it in scope, and it's
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potentially unclear when it's being used (extension traits), but it does get the basic job done.
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# Trait objects as arguments
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Handled as part of `decltype` and compiler-named types, not sure it needs it's own section.
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```rust
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trait MyTrait {
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fn some_method(&self);
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}
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fn my_function(value: &dyn MyTrait) {
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}
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```
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C++ can't explicitly use vtable as part of concepts:
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```c++
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template<typename T, typename = std::enable_if_t<...>>
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void my_function(T& value) {}
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```
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...is equivalent to:
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```rust
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fn my_function<T: MyTrait>(value: &T) {}
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```
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Alternate form with concepts:
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```c++
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#include <concepts>
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#include <cstdint>
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template<typename T>
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concept HasMethod = requires (T a) {
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{ a.some_method() } -> std::same_as<std::uint64_t>;
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};
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auto my_function(HasMethod auto value) {
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auto x = value.some_method();
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}
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class MyClass {
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public:
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std::uint64_t some_method() {
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return 42;
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}
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};
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int main() {
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auto x = MyClass {};
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my_function(x);
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}
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```
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vtable is automatically used if virtual, but concepts (so far as I can tell) can't detect virtual.
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Kind of nice because you don't have to explicitly manage the vtable in Rust, but you trade off the
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ability to get inheritance. Modern trends have been "composition over inheritance" (see Google style
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docs as an example) so the trend may be worth it, but moving away from inheritance models is
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disorienting.
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`dyn Trait` seems to be used in Rust mostly for type erasure - `Box<Pin<dyn Future>>` for example,
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but is generally fairly rare, and C++ probably doesn't suffer for not having it. Can use inheritance
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to force virtual if truly necessary, but not sure why you'd need that.
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